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Siio
2017-08-17 11:32:15
1 2 3 4 5 6 7 8 9 10 11 12 | -- GROUP BY 语法: -- SELECT column_name, function(column_name) -- FROM table_name -- WHERE column_name operator value -- GROUP BY column_name; SELECT gender, COUNT (*) FROM user1 GROUP BY gender; -- 或者 SELECT id, username, gender FROM user1 GROUP BY gender, id, username; |
恭喜解决一个难题,获得1积分~
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