列表中的字典如何按照key排序

请帮忙看下我这段代码中querycount（）方法的问题。

# coding:utf-8

class BankAccount(object):

def __init__(self, init_money):
self.total_money = init_money
self.counts = []
def querycount(self):
print('===============================交易记录====================================')

        
      self.counts.sort(key=lambda x: x['交易时间'])
for i in self.counts:

print(i)

def deposit(self, money, currency, des, deal_time_str):
self.total_money += money
        msg = "交易时间:%s \t摘要:%s \t金额:+%.2f \t币种:%s \t余额:%.2f" % (deal_time_str, des, money, currency, self.total_money)
print(msg)
self.counts.append(msg)

def withdraw(self, money, currency, des, deal_time_str):
self.total_money -= money
        msg = "交易时间:%s \t摘要:%s \t金额:-%.2f \t币种:%s \t余额:%.2f" % (deal_time_str, des, money, currency, self.total_money)
print(msg)
self.counts.append(msg)


if __name__ == "__main__":
    account = BankAccount(5380)
    account.withdraw(5000, "人民币", "网转", "2020-03-06")
    account.deposit(500, "人民币", "转入", "2020-05-08")
    account.withdraw(100, "人民币", "消费", "2020-08-10")
    account.withdraw(101.0, "人民币", "消费", "2020-12-25")
    account.deposit(27800, "人民币", "转入", "2021-01-05")
    account.querycount()

self.counts.reverse()
for i in self.counts:
print(i)

这样就行了