老师帮我看下代码 报错了 不知道怎么解决
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<link rel="stylesheet" href="./css/base.css">
<link rel="stylesheet" href="./font/iconfont.css">
<title>dropDown</title>
<style>
.dropdown {
position: relative;
/* margin: 150px; */
}
.dropdown-toggle {
position: relative;
z-index: 2;
}
/* 下拉箭头 */
.dropdown-arrow {
display: inline-block;
/* text-align: center; */
vertical-align: text-top;
}
.dropdown-layer {
display: none;
overflow: hidden;
position: absolute;
z-index: 1;
}
.dropdown-left {
left: 0;
right: auto;
}
.dropdown-right {
right: 0;
left: auto;
}
/* menu dropdown */
.menu .dropdown-toggle {
display: block;
height: 100%;
padding: 0 16px 0 12px;
border-left: 1px solid #f3f5f7;
border-right: 1px solid #f3f5f7;
}
.menu .dropdown-arrow {
margin-left: 5px;
}
.menu .dropdown-layer {
/* top: 44px; */
top: 100%;
border: 1px solid #cdd0d4;
/* border-top: none; */
background-color: #fff;
}
.menu-item {
display: block;
height: 30px;
padding: 0 12px;
line-height: 30px;
white-space: nowrap;
color: #4d555d;
}
.menu-item:hover {
background-color: #f3f5f7;
}
/* css hover 实现显示隐藏 */
.menu-active .dropdown-toggle {
background-color: #fff;
border-color: #cdd0d4;
}
/* 下拉箭头效果 */
[class *= "-active"] .dropdown-arrow {
-o-transform: rotate(180deg);
-ms-transform: rotate(180deg);
-moz-transform: rotate(180deg);
-webkit-transform: rotate(180deg);
transform: rotate(180deg);
}
.transition {
-o-transition: all 0.5s;
-ms-transition: all 0.5s;
-moz-transition: all 0.5s;
-webkit-transition: all 0.5s;
transition: all 0.3s;
}
/* .menu-active .dropdown-layer {
display: block;
} */
/* 显示隐藏效果 */
.fadeOut {
visibility: hidden !important;
opacity: 0 !important;
}
.slideUpDownCollapse {
height: 0 !important;
padding-top: 0 !important;
padding-bottom: 0 !important;
}
.slideLeftRightCollapse {
width: 0 !important;
padding-left: 0 !important;
padding-right: 0 !important;
}
</style>
</head>
<body>
<div class="menu dropdown fl" data-active="menu">
<a href="" class="dropdown-toggle">我的慕淘<i class="iconfont dropdown-arrow transition"></i></a>
<ul class="dropdown-layer dropdown-left">
<li><a href="###" class="menu-item">已买到宝贝</a></li>
<li><a href="###" class="menu-item">我的足迹</a></li>
</ul>
</div>
<script src="./js/jquery.js"></script>
<script src="./js/transition.js"></script>
<script src="./js/showHide.js"></script>
<script src="./js/dropDown.js"></script>
<script>
$('.dropdown').dropdown({
css3: true,
js: true,
animation: 'slideUpDown',
active: 'menu'
});
</script>
</body>
</html>(function ($) {
'use strict';
// Constructor
function Dropdown(elem, options) {
this.$elem = $(elem),
this.$layer = this.$elem.find('.dropdown-layer'),
this.activeClass = options.active + '-active';
this.$layer.showHide(options);
this.$elem.hover($.proxy(this.show, this), $.proxy(this.hide, this));
}
Dropdown.DEFAULTS = {
css3: false,
js: false,
animation: 'fade',
active: 'dropdown'
};
Dropdown.prototype.show = function () {
// console.log(this);
this.$elem.addClass(this.activeClass);
this.$layer.showHide('show');
};
Dropdown.prototype.hide = function () {
this.$elem.removeClass(this.activeClass);
this.$layer.showHide('hide');
};
var dropdown = new Dropdown();
dropdown.show();
dropdown.hide();
$.fn.extend({
dropdown: function (option) {
return this.each(function () {
var options = $.extend({}, Dropdown.DEFAULTS, option);
new Dropdown(this, options);
});
}
});
})(jQuery);
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2回答
同学你好，针对你截图的报错信息，在dropdown.js文件里面，把下列代码去掉就可以了。
如果我的回答帮助到了你，欢迎采纳，祝学习愉快~
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