这是啥意思

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提问者 慕无忌0089299 2018-07-25 14:14:38

信息: At least one JAR was scanned for TLDs yet contained no TLDs. Enable debug logging for this logger for a complete list of JARs that were scanned but no TLDs were found in them. Skipping unneeded JARs during scanning can improve startup time and JSP compilation time.

7月 25, 2018 10:19:00 上午 org.apache.jasper.servlet.TldScanner scanJars

信息: At least one JAR was scanned for TLDs yet contained no TLDs. Enable debug logging for this logger for a complete list of JARs that were scanned but no TLDs were found in them. Skipping unneeded JARs during scanning can improve startup time and JSP compilation time.

7月 25, 2018 10:19:00 上午 org.apache.jasper.servlet.TldScanner scanJars

信息: At least one JAR was scanned for TLDs yet contained no TLDs. Enable debug logging for this logger for a complete list of JARs that were scanned but no TLDs were found in them. Skipping unneeded JARs during scanning can improve startup time and JSP compilation time.

7月 25, 2018 10:19:00 上午 org.apache.coyote.AbstractProtocol start

信息: Starting ProtocolHandler ["http-nio-8080"]

问题应该是在这里吧

就是老师上课的那些 自己试了下 不行http://img1.sycdn.imooc.com//climg/5b58153300017e5012380683.jpg

  • 根据错误提示来看,你的jsp页面应该出现问题了,导致tomcat解析时出现了问题,建议你将jsp页面的代码和LoginServlet中的代码粘贴到回答中,或新建一问答,方便助教老师帮你调试代码,具有针对性的帮助你解决问题。祝学习愉快~
    2018-07-25 14:47:43
  • 提问者 慕无忌0089299 #2
    <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1"> <display-name>ServletText</display-name> <welcome-file-list> <welcome-file>index.html</welcome-file> <welcome-file>index.htm</welcome-file> <welcome-file>index.jsp</welcome-file> <welcome-file>default.html</welcome-file> <welcome-file>default.htm</welcome-file> <welcome-file>default.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>LoginServlet</servlet-name> <servlet-class>cn.java.servlet.LoginServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>LoginServlet</servlet-name> <url-pattern>/LoginServlet</url-pattern> </servlet-mapping> </web-app>
    2018-07-25 15:38:19
  • chrismorgen 回复 提问者 慕无忌0089299 #3
    我在http://class.imooc.com/course/qadetail/61165这个问答中给你回复了,祝学习愉快~
    2018-07-25 17:15:23
chrismorgen 2018-07-25 11:33:31

这是tomcat运行时的一些信息,同学代码报的什么错?请具体描述问题并将报错信息帖全,方便助教老师们具有针对性的帮助你解答问题,祝学习愉快~

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